A man buy 3 accessories with 100 rupees. first one 5 rupees, second one 3 rupees, third one 0.5 rupees each. he bought total 100 pieces. How many pieces he bought for each accessory ?

First Accessory

Second Accessory

Third Accessory

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lets say he bought x,y and z pieces.

Then we can make these two equations

Eq1: x + y + z = 100

Eq2: 5x + 3y + 0.5z = 100

Then we can make these two equations

Eq1: x + y + z = 100

Eq2: 5x + 3y + 0.5z = 100

2*Eq2 => 10x + 6y + z = 200

2*Eq2-Eq1 => 9x + 5y = 100

from this equation x should be a multiple of 5, for x = 5 => y = 11

for x = 10 => y = 2

for x = 15 or more y becomes -ve

So two possible answers

x = 5, y = 11, z = 84

x = 10, y = 2, z = 88

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rohit says

A man buy 3 accessories with 100 rupees. first one 5 rupees, second one 10 rupees, third one 0.5 rupees each. he bought total 100 pieces. How many pieces he bought for each accessory ?

BL kumawat says

No. Of pieces of Rs.5 =10

No. Of pieces of Rs.3 =2

No. Of pieces of Rs.0.5 = 88

Total no. Of pieces = 100

Total cost = (5*10)+(3*2)+(0.5*88)=100

abd says

Wow. The grammar here is awful and needs to be rewritten so that it is easier to understand what the actual question is. I had to read it 5 times before I could tell what the question was actually asking, and what information was actually given.